Hello BWR,

Don't know why anyone hasn't answered this yet, but I'll give it a shot.

please understand that I'm a newbie so this may be wrong, so I'm open to correction. So here goes

As I understand it, the gain of anything is 20log voltage out/ voltage in. So to figure the gain, we need to figure the voltage across the secondary of the output tranny with a known input voltage. Steve lists the output power at 2 watts into 8 ohms with a 2 volt input. We know that P= E x I, and E= I x R, so a littlle

configuring

gives us E= square root of ( PR ). Substituting known values gives us a voltage across the output tranny of 4 with an input of 2 volts. Substituting into the gain equation yields 20 log(4/2), or a gain of 6.02db.

I think I've got it right, but again guys, if not, please correct.

Bill